mysqli_result::field_seek
If you are getting this error:
Internal SQL Bug: 2014, Commands out of sync; you can't run this command now
Then you never called mysqli_result::free(), mysqli_result::free_result(), mysqli_result::close(), or mysqli_free_result() in your script, and must call it before executing another stored procedure.
mysqli_result::free
mysqli_free_result
(PHP 5)
mysqli_result::free -- mysqli_free_result — Frees the memory associated with a result
Descripción
Estilo orientado a objetos
void mysqli_result::free
( void
)
void mysqli_result::close
( void
)
void mysqli_result::free_result
( void
)
Estilo por procesos
void mysqli_free_result
( mysqli_result $result
)
Frees the memory associated with the result.
Note:
You should always free your result with mysqli_free_result(), when your result object is not needed anymore.
Parámetros
- result
-
Sólo estilo procedimental: Un conjunto de identificadores de resultados devuelto por mysqli_query(), mysqli_store_result() o mysqli_use_result().
Valores devueltos
No devuelve ningún valor.
Ver también
- mysqli_query() - Performs a query on the database
- mysqli_stmt_store_result() - Transfers a result set from a prepared statement
- mysqli_store_result() - Transfers a result set from the last query
- mysqli_use_result() - Initiate a result set retrieval
add a note
User Contributed Notes
mysqli_result::free
Vector at ionisis dot com
29-Dec-2009 01:17
Anonymous
18-Oct-2009 10:49
Freeing the memory associated with a result means that the references returned by mysqli_fetch_object (or equivalent) are cleared. Thus if you should pass an object pointing to a database row _by reference_, every call of mysqli_free_result will discard the referenced data.