chdir

(PHP 4, PHP 5)

chdir — Cambia de directorio

Descripción

bool chdir ( string $directory )

Cambia el directorio actual de PHP a directorio.

Parámetros

directorio: El nuevo directorio actual.

Valores devueltos

Devuelve TRUE en caso de éxito o FALSE en caso de error.

Ejemplos

Example #1 chdir() ejemplo


<?php
 
// directorio actual
echo getcwd() . "\n";
 
chdir('public_html');
 
// directorio actual 
echo getcwd() . "\n";
 
?>

El resultado del ejemplo sería algo similar a:

/home/vincent
/home/vincent/public_html

Notas

Note: Cuando safe mode está habilitado, PHP comprueba si el directorio en el que el script está operando tiene el mismo UID (propietario) que el script que está siendo ejecutado.

Ver también

getcwd() - Obtiene el directorio actual en donde se esta trabajando

chroot

Funciones de directorio

Last updated: Fri, 20 May 2011

add a note User Contributed Notes chdir

php dot duke at qik dot nl 31-Jan-2009 10:16


When changing dir's under windows environments:





<?php


$path="c:\temp"';


chdir($path);


/* getcwd() gives you back "c:\temp" */





$path="c:\temp\"';


chdir($path);


/* getcwd() gives you back "c:\temp\" */


?>





to work around this inconsistency


doing a chdir('.') after the chdir always gives back "c:\temp"

andy dot clark at dial dot pipex dot com 21-Aug-2006 03:10


This only changes the directory for PHP, the output directory stays the same. If you are trying to access images from a relative path and you use the following then it will fail to render the image:



chdir ('images');

if (file_exists('php.gif')) 

{

echo '<html>';

echo '<body>';

echo '<img src="php.gif">';

echo '</body></html>';

}



//However, it is possible to use the <base> tag in the header to change the directory for the resulting HTML, as you can see however this requires you to put the full path in place.



chdir ('images');

if (file_exists('php.gif')) 

{

echo '<html>';

echo '<head><base href = "http://uk.php.net/images/"></head>';

echo '<body>';

echo '<img src="php.gif">';

echo '</body></html>';

}

herwin at snt dot utwente dot nl 17-Aug-2006 06:58


When using PHP safe mode and trying to change to a dir that is not accessible due to the safe mode restrictions, the function simply fails without generating any kind of error message.



(Tested in PHP 4.3.10-16, Debian Sarge default)

jeprubio _At_ gmail dot com 27-May-2005 07:25


If you run this script when $sym_dir is a symbolic link to a directory:

  echo getcwd()."\n";

  chdir ($sym_dir);

  chdir ('../');

  echo getcwd()."\n";



It returns for example:

  /dades/loc/real/mapes/navteq/anloc

  /mapes/anloc



It will not return to the previous directory, it returns to the parent of the real directory where it links the symbolic link.



It's not necessary a bug but I think it's important to have present this.



It could be solved saving the current directory and then returning to it. For example:

  $cwd = getcwd();

  echo getcwd()."\n";

  chdir ($sym_dir);

  chdir ($cwd);

  echo getcwd()."\n";



It returns:

  /dades/loc/real/mapes/navteq/anloc

  /dades/loc/real/mapes/navteq/anloc



Have fun :)

-------

   Josep Rubio (Anloc S.L. www.anloc.net)

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